Optimal. Leaf size=335 \[ -\frac {7 d^{3/2} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}-\frac {7 d^{3/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3} \]
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Rubi [A] time = 0.35, antiderivative size = 335, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 10, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {28, 288, 290, 329, 211, 1165, 628, 1162, 617, 204} \begin {gather*} -\frac {7 d^{3/2} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}-\frac {7 d^{3/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 28
Rule 204
Rule 211
Rule 288
Rule 290
Rule 329
Rule 617
Rule 628
Rule 1162
Rule 1165
Rubi steps
\begin {align*} \int \frac {(d x)^{3/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx &=b^4 \int \frac {(d x)^{3/2}}{\left (a b+b^2 x^2\right )^4} \, dx\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {1}{12} \left (b^2 d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )^3} \, dx\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}+\frac {\left (7 b d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )^2} \, dx}{96 a}\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}+\frac {\left (7 d^2\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )} \, dx}{128 a^2}\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}+\frac {(7 d) \operatorname {Subst}\left (\int \frac {1}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{64 a^2}\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}+\frac {7 \operatorname {Subst}\left (\int \frac {\sqrt {a} d-\sqrt {b} x^2}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{128 a^{5/2}}+\frac {7 \operatorname {Subst}\left (\int \frac {\sqrt {a} d+\sqrt {b} x^2}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{128 a^{5/2}}\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}-\frac {\left (7 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {d x}\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}-\frac {\left (7 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {d x}\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}+\frac {\left (7 d^2\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {d x}\right )}{256 a^{5/2} b^{3/2}}+\frac {\left (7 d^2\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {d x}\right )}{256 a^{5/2} b^{3/2}}\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}-\frac {7 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}+\frac {\left (7 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}-\frac {\left (7 d^{3/2}\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}\\ &=-\frac {d \sqrt {d x}}{6 b \left (a+b x^2\right )^3}+\frac {d \sqrt {d x}}{48 a b \left (a+b x^2\right )^2}+\frac {7 d \sqrt {d x}}{192 a^2 b \left (a+b x^2\right )}-\frac {7 d^{3/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}-\frac {7 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{11/4} b^{5/4}}\\ \end {align*}
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Mathematica [A] time = 0.13, size = 260, normalized size = 0.78 \begin {gather*} \frac {d \sqrt {d x} \left (-\frac {21 \sqrt {2} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{a^{11/4} \sqrt {x}}+\frac {21 \sqrt {2} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{a^{11/4} \sqrt {x}}-\frac {42 \sqrt {2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{a^{11/4} \sqrt {x}}+\frac {42 \sqrt {2} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}+1\right )}{a^{11/4} \sqrt {x}}+\frac {56 \sqrt [4]{b}}{a^2 \left (a+b x^2\right )}+\frac {32 \sqrt [4]{b}}{a \left (a+b x^2\right )^2}-\frac {256 \sqrt [4]{b}}{\left (a+b x^2\right )^3}\right )}{1536 b^{5/4}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.78, size = 213, normalized size = 0.64 \begin {gather*} -\frac {7 d^{3/2} \tan ^{-1}\left (\frac {\frac {\sqrt [4]{a} \sqrt {d}}{\sqrt {2} \sqrt [4]{b}}-\frac {\sqrt [4]{b} \sqrt {d} x}{\sqrt {2} \sqrt [4]{a}}}{\sqrt {d x}}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}+\frac {7 d^{3/2} \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d} \sqrt {d x}}{\sqrt {a} d+\sqrt {b} d x}\right )}{128 \sqrt {2} a^{11/4} b^{5/4}}+\frac {\sqrt {d x} \left (-21 a^2 d^7+18 a b d^7 x^2+7 b^2 d^7 x^4\right )}{192 a^2 b \left (a d^2+b d^2 x^2\right )^3} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.68, size = 373, normalized size = 1.11 \begin {gather*} \frac {84 \, {\left (a^{2} b^{4} x^{6} + 3 \, a^{3} b^{3} x^{4} + 3 \, a^{4} b^{2} x^{2} + a^{5} b\right )} \left (-\frac {d^{6}}{a^{11} b^{5}}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {d x} a^{8} b^{4} d \left (-\frac {d^{6}}{a^{11} b^{5}}\right )^{\frac {3}{4}} - \sqrt {a^{6} b^{2} \sqrt {-\frac {d^{6}}{a^{11} b^{5}}} + d^{3} x} a^{8} b^{4} \left (-\frac {d^{6}}{a^{11} b^{5}}\right )^{\frac {3}{4}}}{d^{6}}\right ) + 21 \, {\left (a^{2} b^{4} x^{6} + 3 \, a^{3} b^{3} x^{4} + 3 \, a^{4} b^{2} x^{2} + a^{5} b\right )} \left (-\frac {d^{6}}{a^{11} b^{5}}\right )^{\frac {1}{4}} \log \left (7 \, a^{3} b \left (-\frac {d^{6}}{a^{11} b^{5}}\right )^{\frac {1}{4}} + 7 \, \sqrt {d x} d\right ) - 21 \, {\left (a^{2} b^{4} x^{6} + 3 \, a^{3} b^{3} x^{4} + 3 \, a^{4} b^{2} x^{2} + a^{5} b\right )} \left (-\frac {d^{6}}{a^{11} b^{5}}\right )^{\frac {1}{4}} \log \left (-7 \, a^{3} b \left (-\frac {d^{6}}{a^{11} b^{5}}\right )^{\frac {1}{4}} + 7 \, \sqrt {d x} d\right ) + 4 \, {\left (7 \, b^{2} d x^{4} + 18 \, a b d x^{2} - 21 \, a^{2} d\right )} \sqrt {d x}}{768 \, {\left (a^{2} b^{4} x^{6} + 3 \, a^{3} b^{3} x^{4} + 3 \, a^{4} b^{2} x^{2} + a^{5} b\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.20, size = 302, normalized size = 0.90 \begin {gather*} \frac {1}{1536} \, d {\left (\frac {42 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{3} b^{2}} + \frac {42 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{3} b^{2}} + \frac {21 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x + \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{3} b^{2}} - \frac {21 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x - \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{3} b^{2}} + \frac {8 \, {\left (7 \, \sqrt {d x} b^{2} d^{6} x^{4} + 18 \, \sqrt {d x} a b d^{6} x^{2} - 21 \, \sqrt {d x} a^{2} d^{6}\right )}}{{\left (b d^{2} x^{2} + a d^{2}\right )}^{3} a^{2} b}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 271, normalized size = 0.81 \begin {gather*} -\frac {7 \sqrt {d x}\, d^{7}}{64 \left (b \,d^{2} x^{2}+d^{2} a \right )^{3} b}+\frac {3 \left (d x \right )^{\frac {5}{2}} d^{5}}{32 \left (b \,d^{2} x^{2}+d^{2} a \right )^{3} a}+\frac {7 \left (d x \right )^{\frac {9}{2}} b \,d^{3}}{192 \left (b \,d^{2} x^{2}+d^{2} a \right )^{3} a^{2}}+\frac {7 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, d \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )}{256 a^{3} b}+\frac {7 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, d \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )}{256 a^{3} b}+\frac {7 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, d \ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )}{512 a^{3} b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 3.02, size = 332, normalized size = 0.99 \begin {gather*} \frac {\frac {8 \, {\left (7 \, \left (d x\right )^{\frac {9}{2}} b^{2} d^{4} + 18 \, \left (d x\right )^{\frac {5}{2}} a b d^{6} - 21 \, \sqrt {d x} a^{2} d^{8}\right )}}{a^{2} b^{4} d^{6} x^{6} + 3 \, a^{3} b^{3} d^{6} x^{4} + 3 \, a^{4} b^{2} d^{6} x^{2} + a^{5} b d^{6}} + \frac {21 \, {\left (\frac {\sqrt {2} d^{4} \log \left (\sqrt {b} d x + \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {\sqrt {2} d^{4} \log \left (\sqrt {b} d x - \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} + \frac {2 \, \sqrt {2} d^{3} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}} + \frac {2 \, \sqrt {2} d^{3} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}}\right )}}{a^{2} b}}{1536 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.27, size = 149, normalized size = 0.44 \begin {gather*} \frac {\frac {3\,d^5\,{\left (d\,x\right )}^{5/2}}{32\,a}-\frac {7\,d^7\,\sqrt {d\,x}}{64\,b}+\frac {7\,b\,d^3\,{\left (d\,x\right )}^{9/2}}{192\,a^2}}{a^3\,d^6+3\,a^2\,b\,d^6\,x^2+3\,a\,b^2\,d^6\,x^4+b^3\,d^6\,x^6}-\frac {7\,d^{3/2}\,\mathrm {atan}\left (\frac {b^{1/4}\,\sqrt {d\,x}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )}{128\,{\left (-a\right )}^{11/4}\,b^{5/4}}-\frac {7\,d^{3/2}\,\mathrm {atanh}\left (\frac {b^{1/4}\,\sqrt {d\,x}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )}{128\,{\left (-a\right )}^{11/4}\,b^{5/4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (d x\right )^{\frac {3}{2}}}{\left (a + b x^{2}\right )^{4}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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